Question

M
For the coagulation of 20 mL of gold sol, 20 mL of
20
NaCl is required. The flocculation value of NaCl is
5
103
104
los
10
50
20​

Answer 1

Answer:

For the coagulation of 20 mL of gold sol, 20 mL of 20 NaCl is required. The flocculation value of NaCl is 50 millimoles of $\frac{M}{20}$  NaCl for coagulation.

Explanation:

In the study of chemistry, flocculation is the process by which colloids emerge from suspension as floc or flakes, either naturally or as a result of the incorporation of such a clarifying agent. Before flocculation, colloids are only suspended in a liquid rather than truly being dissolved in a solution, which is how the activity differs from precipitation.

The flocculation value is the lowest concentration of an electrolyte needed to generate flocculation or coagulation of a solution. Millimoles per litre are used to measure flocculation value.

Therefore,

20 mL of $\frac{M}{20}$ NaCl contains = 20×$\frac{1}{20}$

20 mL of $\frac{M}{20}$ NaCl contains = 1 millimole

1 millimole of NaCl for coagulation is required for 20 ml of gold

Hence, 1000 mL of Gold requires = 1 × $\frac{1000}{20}$

1000 mL of Gold requires = 50 millimoles of NaCl

To know more about coagulation, visit:

https://brainly.in/question/33771949

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https://brainly.in/question/9006022

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