Find the 17th term of the G. P 2,2√2,4,8√2......
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Tn = ar^n-1
a=2 , r= 2√2/2=√2
t17= 2 ×(√2)^16
=2×256
=512
a=2 , r= 2√2/2=√2
t17= 2 ×(√2)^16
=2×256
=512
Bibekgurung:
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