find the 18th term of the AP 1 ,6, 11, 16
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Answered by
10
t1= 1, t2= 6, t3= 11, t4= 16 d =t2-t1 = 6-1 = 5
tn = a+d (n-1)
t18 = 1+5(18-1)
= 1+5x 17
= 1+85
= 86
Answered by
5
Answer:
a=1, d=6-1= 5,n=18, an=?
an=a+(n-1)d
an=1+(18-1)5
an=18×5
an=90
A18=90
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