Question

write the electronic configuration of two elements P atomic number 17 and q atomic number 19 and determine their group numbers and period number in the modern periodic table​

Answer 1

Answer:

for atomic no 17 = 1s2 2s2 2p6 3s2 3p5

for atomic no 19 = 1s2 ,2s2 2p6 3s2 3p6 4s1

the atomic no 17 is chlorine from pblock

17 group 3 period

the atomic no 19 is potassium from s

block

Answer 2

Element with atomic number 17 belongs to period 3 and group 17.

Element with atomic number 19 belongs to period 4 and group 1.

Explanation:

Element with atomic number 17 will have the electronic configuration as follows.

        $1s^{2}2s^{2}2p^{6}3s^{2}3p^{5}$

Since, there are 3 shells present hence, this element belongs to period 3 and group 17 (as there are 7 valence electrons).

And, element with atomic number 19 will have electronic configuration as $1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{1}$.

This element belongs to group 1 as there is only one valence electron and it lies in period 4 of the modern periodic table.

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