find
the 18th term of the AP
2,5, 8
11,.........
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Given :
- A.P. = 2,5, 8, 11,...
To find :
- 18th term
Formula used :
- Tn = a+(n-1)d
where :-
- a = first term
- n = number of terms
- d = common difference
- Tn = nth term
Solution :
From the given AP we know that :-
first term = 2
⟹common difference = second term - first term
⟹common difference = 5 - 2
⟹common difference = 3
To find 18th term we will use the following formula :-
⟹ Tn = a+(n-1)d
Now put :-
- a = 2
- n = 18
- d = 3
- Tn = T18
⟹ Tn = a+(n-1)d
⟹ T18 = 2+(18-1)3
⟹ T18 = 2+51
⟹ T18 = 53
Answer :
Therefore , 18th term of given A.P = 53
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Learn more :
1. Tn = a+(n-1)d
2. Sn = n/2[2a+(n-1)d]
3. Sn = n/2(a+l)
where :-
- a = first term
- n = number of terms
- d = common difference
- Tn = nth term
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