find the 19 th term of A P: :2,9,16......
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128 is the answer. .......................
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A1=2
a2= 9
D=a2-a1
D=9-2=7
an={a+(n-1)×d}
a19={2+(19-1)7}
={2+18×7}
={2+126}
=128. answer
a2= 9
D=a2-a1
D=9-2=7
an={a+(n-1)×d}
a19={2+(19-1)7}
={2+18×7}
={2+126}
=128. answer
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