find the 1st 3 TERMS OF AN AP OF 3rd TERM 11 AND SUM OF 1st 3 TERMS 21
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1st term = a
Second term = a + d
Third term = a + 2d
=============
Here,
Third term = 11
a + 2d = 11
a = 11 - 2d ----1equation
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Sum of 1st 3 term = 21
a + a +d + a + 2d = 21
Putting the value of a from 1equation,
11 - 2d + 11- 2d + d + 11- 2d + 2d = 21
=> 33 -3d = 21
=> 33 - 21 = 3d
=> 12 = 3d
=> 12/3 = d
=> 4 = d
Putting the value of d in 1equation,
a = 11 - 2d
a = 11 - 2(4)
a = 11 - 8
a = 3
================
3 terms of ap are:-
a = 3
a + d = 3 + 4 = 7
a +2d = 3+8 = 11
I hope this will help you
-by ABHAY
Second term = a + d
Third term = a + 2d
=============
Here,
Third term = 11
a + 2d = 11
a = 11 - 2d ----1equation
---------------------
Sum of 1st 3 term = 21
a + a +d + a + 2d = 21
Putting the value of a from 1equation,
11 - 2d + 11- 2d + d + 11- 2d + 2d = 21
=> 33 -3d = 21
=> 33 - 21 = 3d
=> 12 = 3d
=> 12/3 = d
=> 4 = d
Putting the value of d in 1equation,
a = 11 - 2d
a = 11 - 2(4)
a = 11 - 8
a = 3
================
3 terms of ap are:-
a = 3
a + d = 3 + 4 = 7
a +2d = 3+8 = 11
I hope this will help you
-by ABHAY
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