Find the 2 of the square whose side is equal to the diagonal of a rectangle of length 3 cm and breadth 4 cm.
A) 25 sq.cm
B) 16 sq.cm
C) 9 sq.cm
D) 4 sq.cm
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In a rectangle, a triangle formed by the two perpendicular sides and diagonal of a rectangle is a right angled triangle (with the diagonal as the hypotenuse).
As per the Pythagoras theorem, the length of the diagonal is equal to the square root of the sum of the squares of the perpendicular sides of the rectangle.
Let the length of the unknown side be x cm.
Therefore by Pythagoras theorem, we can state that (4.5)^2 + x^2 = (7.5)^2
Therefore x^2 = 56.25 - 20.25 = 36.
Thus x = 6.
Hence the lengths of the sides of the rectangle are 4.5 cms and 6 cms.
Area of a rectangle is equal to the product of the lengths of the sides, meaning 4.5 × 6 = 27.
Hence area of the rectangle is 27 squats centimetres.
As per the Pythagoras theorem, the length of the diagonal is equal to the square root of the sum of the squares of the perpendicular sides of the rectangle.
Let the length of the unknown side be x cm.
Therefore by Pythagoras theorem, we can state that (4.5)^2 + x^2 = (7.5)^2
Therefore x^2 = 56.25 - 20.25 = 36.
Thus x = 6.
Hence the lengths of the sides of the rectangle are 4.5 cms and 6 cms.
Area of a rectangle is equal to the product of the lengths of the sides, meaning 4.5 × 6 = 27.
Hence area of the rectangle is 27 squats centimetres.
Answered by
1
Hii dear Here is ur answer
Option a is the right answer
Hope its help u
Option a is the right answer
Hope its help u
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