The perimeter of a rectangle whose length is 6 m more than its breadth is 84 m. What will be the 2 of the rectangle?
A) 333 sq.mts
B) 330 sq.mts
C) 362 sq.mts
D) 432 sq.mts
Answers
Answered by
0
Q:
The perimeter of a rectangle whose length is 6 m more than its breadth is 84 m. What will be the area of the rectangle?
A) 333 sq.mtsB) 330 sq.mtsC) 362 sq.mtsD) 432 sq.mts
Answer: D) 432 sq.mts
Explanation:
Let the breadth of the rectangle = b mts
Then Length of the rectangle = b + 6 mts
Given perimeter = 84 mts
2(L + B) = 84 mts
2(b+6 + b) = 84
2(2b + 6) = 84
4b + 12 = 84
4b = 84 - 12
4b = 72
b = 18 mts
=> Length = b + 6 = 18 + 6 = 24 mts
Now, required Area of the rectangle =L x B = 24 x 18 = 432 sq. mts
Answered by
0
Hii dear Here is ur answer
Option d is the right answer
Hope its help u
Option d is the right answer
Hope its help u
Similar questions