Question

find the 2 parallel sides of a trapazium whose area is 1.6 m^2 , attitude is 10 dm and 1 parallel sides is longer than other by 8 dm ​

Answer 1

Answer:

Given: Base of trapezium (b

1

)=12 dm=

10

12

m=1.2 m[∵1 dm=

10

1

m]

Base of trapezium (b

2

)=20 dm=

10

20

m=2 m

Height of trapezium (h)=10 dm=

10

10

m=1 m

Now, Area of trapezium =

2

1

×(b

1

+b

2

)×h

=

2

1

×(1.2+2)×1

=1.6 m

2