How much
An aluminium wire has
a diameter of 0.5mm
and a resistivity of 2.6 X10-8 m
how much is of this wire would be necessary to make a
resistance of 10ohm?
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Answered by
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Given
Resistivity = 2.6* 10^-8
diameter = 0.5mm
Radius = 0.5/2=0.25mm
Area= pi*r^2=3.14*0.25*0.25= 1.962 * 10^-7m^2
Resistance = 10 ohm
R= resistivity*length/area
10= (2.6*10^-8/1.962*10^-7)L
L= 19.62/0.26
L= 75.46m
Resistivity = 2.6* 10^-8
diameter = 0.5mm
Radius = 0.5/2=0.25mm
Area= pi*r^2=3.14*0.25*0.25= 1.962 * 10^-7m^2
Resistance = 10 ohm
R= resistivity*length/area
10= (2.6*10^-8/1.962*10^-7)L
L= 19.62/0.26
L= 75.46m
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