Question

Find+the+20+of+the+ap+3+5+7+9+11

Answer 1

Given,

$a_{1} = 3 \\ \\ a_{2} = 5 \\ \\ d = a_{2} - a_{1} \\ d = 5 - 3 \\ d = 2 \\ \\ a = 3 \\ \\ n = 20$

Putting the value in the formula:

$a_{n} = a + (n - 1)d$

= 3 + (20 - 1)2

= 3 + (19)2

= 3 + 38

= 41