Question

Find the 20th term from the end of the AP 3,8,13..........253​

Answer 1

Given ,

First term (a) = 3

Common difference (d) = 5

Last term (l) = 253

We know that , the nth term from end of an AP is given by

$\boxed{ \tt{ a_{n} = l - (n - 1)d}}$

Thus ,

$\tt \implies a_{20} = 253 - (20 - 1)(5)$

$\tt \implies a_{20} =253 - 19 \times 5$

$\tt \implies a_{20} =253 - 95$

$\tt \implies a_{20} =158$

Therefore , the 20th term from the end of the AP is 158

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Answer 2

Explanation:

Refer to the attachment dear......