Find the 20th term of AP 15,12,9,6....
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Hey here is the answer.
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Hope this Will help you
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hosmathprajwal74:
I took the difference as 3
So got it around 72 thank u
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HEY Buddy.....!! here is ur answer
Given that : a1 = 15 , n = 20
12–15 = –3
9–12 = –3
6–9 = –3
Hence , d = –3
As we know that : An = a1 +(n–1)d
=> A(20) = 15 + (20–1)(–3)
=> A(20) = 15 + 19(–3)
=> A(20) = 15–57
=> A(20) = -42
Thus, the 20th term of the A.P. series
I hope it will be helpful for you....!!
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MARK IT AS BRAINLIEST
Given that : a1 = 15 , n = 20
12–15 = –3
9–12 = –3
6–9 = –3
Hence , d = –3
As we know that : An = a1 +(n–1)d
=> A(20) = 15 + (20–1)(–3)
=> A(20) = 15 + 19(–3)
=> A(20) = 15–57
=> A(20) = -42
Thus, the 20th term of the A.P. series
I hope it will be helpful for you....!!
THANK YOU ✌️✌️
MARK IT AS BRAINLIEST
Thank you buddy
Ur most welcome ☺️
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