Question

find the 22rd term

mate help in this ​

Answer 1

Step-by-step explanation:

Let the AP be

a,a+d,a+2d,........,a+(n−1)d

Now, r th term

Tr=a+(r−1)d

∴T4 =a+(4−1)d=a+3d

also, T 18 =a+(18−1)d=a+17d

Given

4(a+3d)=18(a+17d)

⇒4a+12d=18a+306d

⇒14a=−294d

⇒a=−21d

then

⇒T22 =a+(n−1)d

=−21d+(22−1)d

=−21d+21d

=0

Answer 2

not sure about answer bro