Question

find the 23rd term of the AP whoose 1st term is 6 and common difference is2​

Answer 1

Answer:

1st term of the AP, a = 6

Common difference of the AP, d = 2

nth term of an AP = a + ( n - 1 ) d

23rd term of the AP = 6 + ( 23 - 1 ) d

= 6 + 22 × 2

= 6 + 44

= 50

Ans. The 23rd term of the AP is 50.