find the 25 th term of the ap
-5,-5/2,0,5/2.....
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hey mate here is your answer.
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HELLO FRND HERE IS UR ANSWER....
-5,-5/2,0,5/2
a=-5
d=t2-t1
=-5/2-(-5)
=-5/2+5
=(-5+10)/2
=5/2
⏩tn=a+(n-1)d
25th term of the AP
t25=-5+(25-1)5/2
=-5+(24)5/2
=-5+12(5)
=-5+60
=55
Hope it's help u.
-5,-5/2,0,5/2
a=-5
d=t2-t1
=-5/2-(-5)
=-5/2+5
=(-5+10)/2
=5/2
⏩tn=a+(n-1)d
25th term of the AP
t25=-5+(25-1)5/2
=-5+(24)5/2
=-5+12(5)
=-5+60
=55
Hope it's help u.
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