Question

find the 25 th term of the ap

-5,-5/2,0,5/2.....

Answer 1

hey mate here is your answer.

Answer 2

HELLO FRND HERE IS UR ANSWER....

-5,-5/2,0,5/2

a=-5

d=t2-t1
=-5/2-(-5)
=-5/2+5
=(-5+10)/2
=5/2

⏩tn=a+(n-1)d

25th term of the AP

t25=-5+(25-1)5/2
=-5+(24)5/2
=-5+12(5)
=-5+60
=55

Hope it's help u.