find the 29th term of an A.P 5,9,13........?
Answers
Answered by
6
Answer:
common difference (d) = 9-5=4
first term (a) = 5
no of terms (n) = 29
So
a(n) = a + ( n-1)d
a (29) = 5 + (29-1)4
= 5+112
= 117
which is the required ans
Answered by
1
Answer:
117
Step-by-step explanation:
a=5
d=9-5=4
a29=a+(n-1)d
=5+(29-1)4
=5+(28)4
=5+112
=117
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