Question

find the 29th term of an A.P 5,9,13........?​

Answer 1

Answer:

common difference (d) = 9-5=4

first term (a) = 5

no of terms (n) = 29

So

a(n) = a + ( n-1)d

a (29) = 5 + (29-1)4

= 5+112

= 117

which is the required ans

Answer 2

Answer:

117

Step-by-step explanation:

a=5

d=9-5=4

a29=a+(n-1)d

=5+(29-1)4

=5+(28)4

=5+112

=117