Question

Find the 3 numbers of an ap whose sum is 12 then their product is 48

Answer 1

Answer:

Step-by-step explanation:

let the numbers be a-d,a,a+d

(a-d)+a+(a+d)=12

a-d+a+a+d=12

3a=12

a=4

(a-d)*a*(a+d)=48

(a^2-d^2)*4=48

16-d^2=12

d^2=4

d=2

Numbers

a-d=4-2=2

a=4

a+d=4+2=6

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Answer 2

Answer:2,4,6

Step-by-step explanation:

2+4+6=12

2×4×6=48