Question

Find the 30th term from the end of the AP 3,8,13....253

Answer 1

Step-by-step explanation:

tn=a+(n-1)d

t30=3+(30-1)x5

=3+29x5

3+145

148 OK

Answer 2

Step-by-step explanation:

3,8,13.....253

Last term ( L ) = 253

d = 8 - 3 = 5

n = 30

Tn = l - ( n - 1 ) d

= 253 - ( 30 - 1 ) 5

= 253 - ( 29 ) 5

= 253 - 145

= 108

Therefor 30 term of AP = 108 Ans

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