Question

find the 30th term of a G.P x,1,1/x,.....​

Answer 1

x,1 1/x,.... ------------>G.P

a=x

Common ratio = 1/x

30th term in G.P = ar²⁹

= x(1/x)²⁹=1/x²⁸

Answer 2

Given ,

• First term (a) = x
• Common ratio (r) = 1/x

We know that , the nth term of an GP is given by

$\boxed{ \tt{ a_{n} = a {(r)}^{n - 1} }}$

Thus ,

$\tt a_{30} = x \times { (\frac{1}{x}) }^{30 - 1}$

$\tt a_{30} = x \times { (\frac{1}{x}) }^{29}$

$\tt a_{30} = x \times \frac{1}{ {(x)}^{29} }$

$\tt a_{30} = \frac{1}{ {(x)}^{28} }$

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