Question

find the 30th term of AP 10,8,6​

Answer 1

Answer:

a=10

d = -2

n = 30

$an = a + (n - 1)d \\ a30 = 10 + (30 - 1)( - 2) \\ a30 = 10 + (29)( - 2) \\ a30 = 10 + ( - 58) \\ a30 = - 48$

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Answer 2

Answer:

-48

Step-by-step explanation:

AP=10,8,6.....

a=10

d=10-8

  =-2

n=30

an=a+(n-1)d

   =10+(30-1)(-2)

   =10+29(-2)

   =10+(-58)

   =-48

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