Find the 31st term of an A.P. whose 11th term is 38 and the 16th term is 73.
Answers
Answer:
178 is the 31st term of AP
Step-by-step explanation:
Given : a11 = 38
a16 = 73
=> an = a + (n-1) d
=> a11 = a + (11-1) d
=> a + 10d = 38 ———— eq 1
=> a16 = a + (16-1) d
=> a + 15d = 73 ———— eq 2
Now subtract eq 1 - 2
It becomes : -5d = -35
=> d = -35/-5
=> d = 7
Now insert the value of d in eq 1
=> a + 70 = 38
=> a = -32
Now 31st term of AP is : n =31
=> an = -32 + (31 - 1) 7
=> a31 = -32 + 210
=> a31 = 178 Answer
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EXPLANATION.
=> 11 th term of an Ap = 38
=> 16 th term of an Ap = 73
To find the 31st term of an Ap.
Formula of Nth term of an Ap
=> An = a + ( n - 1 ) d
=> 11th term = 38
=> a + 10d = 38 .......(1)
=> 16th term = 73
=> a + 15d = 73 .......(2)
From equation (1) and (2) we get,
=> - 5d = - 35
=> d = 7
put the Value of d = 7 in equation (1)
we get,
=> a + 10(7) = 38
=> a + 70 = 38
=> a = -32
Therefore,
31 st term of an Ap
=> a + 30d
=> -32 + 30(7)
=> -32 + 210
=> 178