Find the 31st term of an AP exceeds its 10th term by 7, find the common difference
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Answered by
14
Hey mate...
here is your answer..
a31= a10+7
a + 30d =a +9d +7
cancelling a on both side
30d=9d +7
30d-9d=7
21d =7
d = 7/21
d = 1/3
here is your answer..
a31= a10+7
a + 30d =a +9d +7
cancelling a on both side
30d=9d +7
30d-9d=7
21d =7
d = 7/21
d = 1/3
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Answered by
5
31st term = a + 30d
10th term = a + 9d
According to the question,
(a + 30d) - (a + 9d) = 7
21d = 7
d = 1/3
Hope this helps..... please make it the brainliest
10th term = a + 9d
According to the question,
(a + 30d) - (a + 9d) = 7
21d = 7
d = 1/3
Hope this helps..... please make it the brainliest
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