find the 31st term of an ap whose 11th term is 38 and the 16th term is 73
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we know tat a 11 = 38 so , a+ 10d =38. a16 = 73 , a+15d = 73. by equating them by elimination method we get d =7 .
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Answered by
16
a+10d=38
a+15d=73
d=7,a=-42
31st term is a+30d
-42+30(7)=168
a+15d=73
d=7,a=-42
31st term is a+30d
-42+30(7)=168
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