Math, asked by djdilip711, 1 year ago

Find the 31st term of an AP whose 11th term is 38 and the 16th term is 73.

Answers

Answered by AniketVerma1
13

let first term of Ap is a and common difference is d

use formula

tn=a+(n-1) d

now

t11=a+(11-1) d=a+10d=38

same way

t16=a+15d=73

solve this equation then

a=-32 and d=7

now t31=a+30d=-32+210=178



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Answered by shivshankar66
7
31 term is 178........

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