Question

find the 31st term of ap whose 11th term is 38 and 16th term is 73

Answer 1

we know tat a 11 = 38 so , a+ 10d =38

a16 = 73 , a+15d = 73

by equating them by elimination method we get d =7

now substitute the vale of d in any of the eq.

we get a +10d=38

a +10[7] =38

a= -32

now we should find out the 31st term so

a31=a +[n-1]d

= -32 +30 * 7

=-32+210

=178

There forethe 31st term is 178...

hope tis will help u ...

Answer 2

hope it help s u.........