find the 35 term of an ap whose 11th term is 38 and 16th term is 73
Answers
Given
T₁₁ = 38
T₁₆ = 73
To find
The value of T₃₅ term
Formula
Tₙ = a+(n-1)d
Now , we get
a + (11-1)d = 38 (i)
a + (16-1)d = 73 (ii)
Now
a+10d = 38 (i)
a+15d = 73 (ii)
Now Subtract (ii) from (i)
a+10d - (a + 15d) = 38-73
a + 10d - a - 15d = -35
-5d = = 35
d = 7
Put the value of d on (i) eq
a+10d = 38 (i)
a + 10(7)=38
a + 70 =38
a = 38 -70
a = -32
Now we have to T₃₅ term
where
a = -32 , d = 7 and n = 35
T₃₅ = a + (35-1)d
T₃₅ = -32 + 34(7)
T₃₅ = -32+238
T₃₅ = 206
Answer
T₃₅ = 206
Given
T₁₁ = 38
T₁₆ = 73
To find
The value of T₃₅ term
Formula
Tₙ = a+(n-1)d
Now , we get
a + (11-1)d = 38 (i)
a + (16-1)d = 73 (ii)
Now
a+10d = 38 (i)
a+15d = 73 (ii)
Now Subtract (ii) from (i)
a+10d - (a + 15d) = 38-73
a + 10d - a - 15d = -35
-5d = = 35
d = 7
Put the value of d on (i) eq
a+10d = 38 (i)
a + 10(7)=38
a + 70 =38
a = 38 -70
a = -32
Now we have to T₃₅ term
where
a = -32 , d = 7 and n = 35
T₃₅ = a + (35-1)d
T₃₅ = -32 + 34(7)
T₃₅ = -32+238
T₃₅ = 206
Answer