Math, asked by narmayachettri71, 4 months ago

find the 35 term of an ap whose 11th term is 38 and 16th term is 73​

Answers

Answered by Anonymous
4

Given

T₁₁ = 38

T₁₆ = 73

To find

The value of T₃₅ term

Formula

Tₙ = a+(n-1)d

Now , we get

a + (11-1)d = 38         (i)

a + (16-1)d = 73         (ii)

Now

a+10d = 38           (i)

a+15d = 73          (ii)

Now Subtract (ii) from (i)

a+10d - (a + 15d) = 38-73

a + 10d - a - 15d = -35

-5d = = 35

d = 7

Put the value of d on (i) eq

a+10d = 38           (i)

a + 10(7)=38

a + 70 =38

a = 38 -70

a = -32

Now we have to T₃₅ term

where

a = -32 , d = 7 and n = 35

T₃₅ = a + (35-1)d

T₃₅ = -32 + 34(7)

T₃₅ = -32+238

T₃₅ = 206

Answer

T₃₅ = 206

Answered by TheBestWriter
1

 \rm \gray{ answer}

Given

T₁₁ = 38

T₁₆ = 73

To find

The value of T₃₅ term

Formula

Tₙ = a+(n-1)d

Now , we get

a + (11-1)d = 38         (i)

a + (16-1)d = 73         (ii)

Now

a+10d = 38           (i)

a+15d = 73          (ii)

Now Subtract (ii) from (i)

a+10d - (a + 15d) = 38-73

a + 10d - a - 15d = -35

-5d = = 35

d = 7

Put the value of d on (i) eq

a+10d = 38           (i)

a + 10(7)=38

a + 70 =38

a = 38 -70

a = -32

Now we have to T₃₅ term

where

a = -32 , d = 7 and n = 35

T₃₅ = a + (35-1)d

T₃₅ = -32 + 34(7)

T₃₅ = -32+238

T₃₅ = 206

Answer

T₃₅ = 206

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