Question

find the 3rd and 9th term of AP are 4 and -8 respectively. which term of this is 0

Answer 1

☆ Hey friend!!! ☆

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Here is your answer ☞
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$according \: to \: your \: question \\ \\ a _{3} = 4 \\ \\ a + 2d \: = 4 \: ......eq _{1} \\ \\ a _{9} = - 8 \\ \\ a + 8d = - 8 \: ........eq _{2} \\ \\ from \: eq _{1} \: and \: eq _{2} \: we \: get \\ \\ d \: = - 2 \\ \\ plug \: the \: value \: of \: d = - 2 \: in \: eq _{1} \: we \: get \\ \\ a = \: 8 \\ \\ we \: know \: that \\ \\ a _{n} \: = \: a + (n - 1) \\ 0 = 8 + (n - 1)( - 2) \\ \\ 0 = 8 - 2n + 2 \\ \\ 2n \: = 10 \\ \\ n \: \: = \: 5 \: ............answer \\ \\ hence \: 5th \: term \: of \: ap \: is \: zero$

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Hope it will help you ☺☺
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Devil_king ▄︻̷̿┻̿═━一

Answer 2

Answer:

Please refer the attachment dear