Question

find the'4' different solutions of the equation 3x+4y=7​

Answer 1

Answer:

Given equation is 3x+4y=7

If x=1 put in equation we get

(i)3×1+4y=7

⇒3+4y=7

⇒4y=7−3

⇒4y=4

⇒y=1

(1,1)

If x=2 put in equation we get

(i)3×2+4y=7

⇒6+4y=7

⇒4y=7−6

⇒4y=1

⇒y=41

(2,41)

If x=3 put in equation we get

(iii)3×3+4y=7

⇒9+4y=7

⇒4y=7−9

⇒4y=−2

⇒y=−42

(3,−42)

Answer 2

Answer:

(-4,4),(1,1),(-7,7),(-11,10) are any 4 solutions

Step-by-step explanation:

3x+4y=7

3x=7-4y

x=(7-4y)/3

if y=1 then

x=(7-(4)(1))\3

x=3/3

x=1

similarly,

if y=7

x= -7

if y=10

x= -11

if y=4

x= -4