find the 40th term of the Ap - 12,-5,2,9......
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Here a = -12 , d= 7 [-5- (-12)]
tn = a + (n-1)d
t40 = -12 +(40-1) 7
t40= -12 + 39*7
t40 = -12 + 276
t40 = 261
Thus, the 40th term of the A. P. is 261 .
I hope this helps you..
tn = a + (n-1)d
t40 = -12 +(40-1) 7
t40= -12 + 39*7
t40 = -12 + 276
t40 = 261
Thus, the 40th term of the A. P. is 261 .
I hope this helps you..
KINGCHAITANYA:
but d=7
sorry.. by mistake
you are an SSC student?
I edited the answer...
ok
yes i am ssc student
ya now correct
all the best for today's paper
plz mark me as branliest
thnx
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