Question

Find the 41st term of the AP :-2 ; 2 ; 6 ; 10 ;..... .formula is (an = a (n-1) d) .​

Answer 1

Answer:

so,a=2 d=0

41st term of a. p= a+40d

=2+40×0

=2+0

=2.

Answer 2

Step-by-step explanation:

AP =-2,2,6,10...

a=-2, d=4

Tn=a+(n-1)d

T41=a+(41-1)d

=-2+40×4

=-2+160

=158

HOPE IT HELPS :)