Question

find the 49th term of the Ap of the sequence 11,22,33,44​

Answer 1

Step-by-step explanation:

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Answer 2

AP = 11, 22, 33, 44.......

Here,

First Term (a) = 11

Common Difference (d) = 22-11 = 11

Index of the term to be determined (n) = 49

Using the relation for nth term of an AP:

T(n) = a + (n-1)d

Thus, T(49) = a + (49-1)d

= 11 + (49-1)11

= 11 + (48)×11

= 11 + 528

= 539

Hence, 49th term of the given AP is 539.