Question

find the 5th term of GP whose 7th term is 729 and common ratios is 1/3​

Answer 1

Answer:

this is the answer...

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Answer 2

Answer:

1/19683

Step-by-step explanation:

nth term of a G.P = ar^(n-1)

7th term = ar^(7-1) = ar^6 = 1/729

Given a = 1 =>> r^6 = 1/729 = (1/3)^6

=>> r = 1/6

10th term = ar^(10-1) = 1×(1/3)^9 = 1/19683

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