Question

Find The 6th term in the expansion of (2x-Y)12.

Answer 1

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Answer 2

Answer:

$^{12}C_5 (2x)^7 (-y)^5$

Step-by-step explanation:

By the binomial theorem,

$(a+b)^n=\sum_{r=0}^{n} ^nC_r (a)^{n-r} (b)^r$

Thus, we can write,

$(2x-y)^{12}=\sum_{r=0}^{12} ^nC_r (2x)^{n-r} (-y)^r$

For the 6th term, r = 5,

Hence, the 6th term of the given expansion is,

$^{12}C_5 (2x)^{12-5} (-y)^5$

$^{12}C_5 (2x)^7 (-y)^5$