find the 6th term when the sum of 6terms are 120 and common difference is 6
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sn= n/2 (2a+(n-1)d)
120= 3(2a+30)
40=2a+30
2a=10
a = 5.
Now,
T6 = a+5d
T6 = 5+30
T6 = 35.
120= 3(2a+30)
40=2a+30
2a=10
a = 5.
Now,
T6 = a+5d
T6 = 5+30
T6 = 35.
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