Question

find the 7th term from the end for ap 11,17,23,29......605

Answer 1

so it is =605+(7-1)-6
605-36
569
ok
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Answer 2

a=11
d=6

l = 605
605 = a +(n-1)d
605 = 11 +(n-1)6
594 = (n-1)6
n-1 = 99
n = 100

Now, The 94th term from the first will be the 7th term from the last

T94 = a +93d
T94 = 11+93*6
T94 = 11 + 558
T94 = 569

Hope it help you

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