Find the 8th term of an ap is 35 and its 102 term is 317 find the AP
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Answer:
a8= 35
a8 can be written as
a+7d
a+7d=35
a102=317
a+101d=317
equating both i and ii we get
a + 7d = 35
a+ 101d=317
94d=282
d=282÷94
d=3
therefore a is 14
a.p is 14,17,20,23
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