Math, asked by bavitha3417, 10 months ago

find the 960th and 961th terms of the sequences An= n/n/96-1,if n is not the square of a natural number=6×1/2,if n is the square of a natural number

Answers

Answered by sshailshetty

2

Answer:

Heya mate your answer

Step-by-step explanation:

T960 = 960 / [960 / 96 -- 1] = 106 4/9

T961 = 961 / [961/96 -- 1] = 106.566/865

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