Question

find the above que answer

Answer 1

may be 110

hope it's help you

Answer 2

Answer:

159

Step-by-step explanation:

It's very simple but quite tricky, let's do three simple steps below to solve this puzzle:

Firstly, let's declare the variables:

a = a couple of people

b = a water bottle

c = a binocular

Secondly, let's analyze the image carefully:

1. On the top picture we can call it Equation 1 or eq. 1 , we can see the picture summarizing three set of a couple of people (a ): ( 1 ) the first left couple bring a water bottle and binocular, thus we can denote it as summation of abc or ∑(abc). ( 2 ) the second image of couple only bring a water bottle, thus we can denote it as ∑(ab), ( 3 ) the third image of the couple only bring a binocular, we can denote it as  ∑(ac).
2. The second row of the picture we can call it eq. 2, where the first, second, and third image are 4 water bottles, 4 water bottles, and 3 water bottles, respectively. Thus adding all of them give 33 as a result.
3. The third row of the picture we can call it eq. 3, where the  first image contains two binocular, and the rest are just a single binocular. The result of this equation is 24.
4. The fourth row of the picture we can call it eq. 4 , where: ( 1 ) the first image is just a single water bottle, ( 2 ) the second image contains two binoculars, and ( 3 ) the third image is a couple who bring a water bottle and a binocular. The result of this equation is unknown (we can denote it as X ). NOTE that this fourth row is tricky, we can see the second operation is a multiplication.

With the descriptions above, we can summarize this picture with these four equations:

(eq. 01):  ∑(abc) + ∑(ab) + ∑(ac) = 30

(eq. 02): 4b + 4b + 3b = 33

(eq. 03): 2c + c + c = 24

(eq. 04): b + 2c x ∑(abc) = X

Lastly, it's time to do some math:

(eq. 02):

4b + 4b + 3b = 33

11b = 33

b = $\frac{33}{11}$

b = 3

(eq. 03):

2c + c + c = 24

4c = 24

c = $\frac{24}{4}$

c = 6

okay now we got the value of b and c, let's find the value of a:

(eq. 01):

∑(abc) + ∑(ab) + ∑(ac) = 30

(a+b+c) + (a+b) + (a+c) = 30

(a+3+6) + (a+3) + (a+6) = 30

a + 9 + a + 3 + a + 6 = 30

3a + 18 = 30

3a = 30 - 18

3a = 12

a = $\frac{12}{3}$

a = 4

Finally we got all the variables, which are a=4, b=3, and c=6. Now let's calculate the final equation:

(eq. 04):

b + 2c x ∑(abc) = X

3 + 2(6) x (4+3+6) = X

3 + 12 x 13 = X

3 + 156 = X

X = 159

That's it, the unknown result from this puzzle is 159