Find the absolute refractive index of water if it's critical angle is 48.5° (sin 48.5=0.75)
Answers
Answered by
1
Answer:
0.75
Explanation:
refractive index = sin i/sin r
RI=sin 48.5/sin 90
RI = 0.75/1=0.75
Similar questions
Math,
5 months ago
Biology,
5 months ago
English,
10 months ago
Social Sciences,
10 months ago
Chemistry,
1 year ago