find the acceleration due to gravity at the surface of a planet of mass 1/5th of the radius 1/2of the earth?
answer please please please
Answers
Answered by
1
Answer:
g' =4/5×g
Step-by-step explanation:
g' = Gm1×m2/r²
= G×1/5×m1×m2/(1/2r²)
= G×m1×m2÷1/4×r²×5
= 4×G×m1×m2/r²×5
g' = 4/5×g
Answered by
1
Answer:
Previous mate has given the correct answer...!!!
Good morning !!
Similar questions