Question

find the acceleration if the initial velocity is 4m/s in time 8.4sec​

Answer 1

Answer:

Explanation:

The acceleration of a particles in ms  

−2

 is given by a=3t  

2

+2t+2, where time t is in second. If the particle starts with a velocity v=2 ms  

−1

 at t=0, then find the velocity at the end of 2 s

a=3t  

2

+2t+2

v=∫  

0

t

​  

adt+c

v(t)=[t  

3

+t  

2

+2t]  

0

t

​  

+c

v(t)=t  

3

+t  

2

+2t+2[c=2m/satt=0]

v(2)=8+4+4+2=18 m/s