Question

$(x {}^{2} - 5x + 7 =$
limit extends to 2(x^2-5x+7)=

substitute 2 in X value

{(2^2)-(5*2)+7}

{4-10+7}

{11-10}

{1}

so,x^2-5x+7=1​

Answer 1

the value of x is 11 - 10 = 1