Question

find the acceleration ignoring gravity and the speed at the bottom of the plane.​

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Acceleration=0.25\:m/s^{2}}}}$

$\green{\tt{\therefore{Final\:velocity=1\:m/s}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}}\\\tt: \implies Distance(s) = 2 \: m \\\\ \tt: \implies Time(t) = 4 \: sec \\\\\red{\underline \bold{To \: Find :}} \\\tt: \implies Acceleration(a) = ? \\\\\tt: \implies Final \: velocity = ?$

• According to given question :

$\tt \circ \: Initial \: velocity = 0 \: m/s \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies s = ut + \frac{1}{2} a {t}^{2} \\ \\ \tt: \implies 2 = 0 \times 4 + \frac{1}{2} \times {a \times 4}^{2} \\ \\ \tt: \implies 2 \times 2 = 16 \times a \\ \\ \tt: \implies a = \frac{4}{16} \\ \\ \green{ \tt: \implies a = 0.25 \: {m/s}^{2} } \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies v = u + at \\ \\ \tt: \implies v = 0 + 0.25 \times 4 \\ \\ \green{\tt: \implies v = 1 \: m/s}$

Answer 2

☢ Given :-

• Distance = 2m.

• Time = 4 seconds.

• Initial Velocity = 0m/s

☢ To Find :-

• Acceleration Of Ball.

• Final Velocity.

☢ Solution :-

Use 3rd Equation Of Motion.

s = ut + ½ at²

Put the values.

➝ 2 = 0×4 + ½ × a × 4²

➝ 2 = 0 + ½ a × 16.

➝ a = 4/16 m/s²

➝ a = 0.25m/s²

Now, Calculating Final Velocity.

Use First Equation Of Motion.

➝ v = u + at.

➝ v = 0 + 0.25 × 4.

➝ v = 1/4 × 4.

➝ v = 1m/s

Hence, Your Answers Are :-

• Acceleration = 0.25m/s²
• Final Velocity = 1m/s