Question

Find the acceleration (m/s) of Cheetah if it acquires the velocity of 135 kmph with in 2s
after the start
a) 25/4
b) 35/4
c) 55/4
d) 75/4


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Answer 1

$\bf{\underline{\overline{\pink{Given :-}}}}$

• Velocity = 135 km/h

• Time = 2 sec

$\bf{\underline{\overline{\purple{To\: Find :-}}}}$

• Acceleration (m/s)

$\bf{\underline{\overline{\red{Solution :-}}}}$

Velocity in m/s

135 × 5/18

⇒ 45 × 5/6

⇒ 225/6

⇒ 75/2

Now,

A = v/t

Where

A = Acceleration

v = velocity

t = time

A = (75/2)/2

A = 75/2 × 1/2

A = 75 × 1/2 × 2

A = 75/4

Thus,

Acceleration is $\bold{75/4 m/s².}$

Answer 2

$\huge\sf \pmb{\orange {\underline \pink{\underline{\:Ꭺ ꪀ \mathfrak ꕶ᭙ꫀя \: }}}}$

Solution :-

• By the given information ,

• Velocity = 135 km/h
• Time taken = 2s

Here the given final velocity is in km/h , so we have to convert into SI units (m/s) .

• ♦ 135 km/h × 5/18 = Velocity in m/s

• ♦ 75/2 = Velocity in m/s

• ♦ Velocity in m/s = 37.5

Now , as we know that

Acceleration = Velocity/Time

⇒ Acceleration = 37.5/2

⇒ Acceleration = (75/2)/2

⇒ Acceleration = 75/2 × 1/2

⇒ Acceleration = 75/4

• Hence , acceleration of the cheetah = 75/4 m/s²

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