Find the acceleration of 5kg block in the given figure:
(g = 10 m/s)
5kg
2 kg
F = 30N
(1) 10 m/s
(2) 5 m/s
(3) 2 m/s
(4) 0 m/s
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Answer:
From FBD of 10 kg block,
F=30N,f=0.1×10×10=10N (Assuming kinetic friction coefficient =0.1)
As F>f , so the 10 kg block will move with acceleration a.
Thus, 10a=F−f=30−10=20⇒a=2m/s
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