Find the acceleration of a truck which is initially moving with a speed of 40km/h and comes to rest after covering a distance of 10m
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Explanation:
Given Find the acceleration of a truck which is initially moving with a speed of 40 km/hr and comes to rest after covering a distance of 10 m
We need to find the acceleration, so given initial velocity u = 40 km/hr = 40 x 1000 / 60 x 60 = 100 /9 m/s, v =0, s = 10 m
So by using equation of motion we get
V^2 = u^2 + 2 a s
0 = (100/9)^2 + 2 a x 10
0 = 10,000 / 81 + 20 a
20 a = - 10000 / 81
a = - 10,000 /81 x 1/20
a = - 500/81
a = - 6.17 m /s^2
So acceleration of the truck is - 6.17 m/s^2
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