If alpha and beta are the zeros of the polynomial p(x)=2x^2-5x+7 find a polynomial whose zeros are are 2alpha + 3beta and 3alpha + 2beta.
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Quadratic equation is of the form ax2+bx+c
now sum of roots=
-b
a
and product of roots=
c
a
here the eqn is 2x2-5x+7 and α and β are its roots.
sum of roots=α+β=
5
2
and product of roots=α×β=
7
2
now we have to form an equation whose roots are 2α+3β and 3α+2β.
equation will be of the form x2-sx+p......(1) where s and p represent sum and product of roots.
s=5(α+β)=
25
2
and p=6((α)2+(β)2)+13αβ)=6(α+β)2+αβ=
6
4
×25+
7
2
=41.
substituting s and p in (1) we get eqn=x2-
25
2
x+41=0.
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