Question

find the acceleration of rod a and wedge b in the arrangement show in figure if the mass of rod equal that of the wedge and the friction between all contact surface is negligible and rod a is free to move downwards only .take angle of wedge as 37

Answer 1

Explanation:

ANSWER

Consider the acceleration of the wedge be a towards right and the acceleration of rod be b downwards

bcos37=acos53 from the contraction of the motion

5

4b

=

5

3a

⇒4b=3a−−−−−−(1)

Now consider the contact force between them is N

Then,

For rod

mg−Ncos37=mb−−−−−−−−(2)

For wedge

Nsin37=ma

⇒N=

3

5ma

−−−−−−−−(3)

Now

mg−

3

5ma

×

5

4

=mb

⇒g−

3

4a

=b

⇒g−

3

4a

=

4

3a

⇒g=

12

16a+9a

⇒25a=120

a=

25

120

=4.8m/s

2

b=

4

3a

=3.6m/s

2

Answer 2

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